Express your answer in terms of v and g. Use three significant figures in the numeric coefficient.
Answer:- At a height of (1/2)hmax, the object’s speed u is 0.707.
The item will only have half of its original kinetic energy at a height that is half of its maximum height; the other half is now transformed into potential energy. so
Thus, the object’s speed at (1/2) hmax height is 0.707 m/s.
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