What is the moment of inertia i of this assembly about the axis through which it is pivoted?

Answer:- 

Explanation:

The moment of inertia for the beam is:

I = 1/12 mt L^2

Where is the mass of the beam and L is the length of the beam

note:

L = 2x

And for particles I is equivalent to:

I = MR^2

where M refers to the mass of the particle and R is the distance between the pivot and the particle.

Lastly, the moment of inertia for this meeting is the sum of the moment of inertia of the particles and the beam. Consequently: