What minimum mass of h2so4 would you need?

Answer:- The balanced chemical equation for the reaction is:

2Al(s)+3H2SO4(aq)→Al2(SO4)3(aq)+3H2(g)

The molar masses of aluminum and sulfuric acid are 26.98 g/mol and 98.079 g/mol respectively.

The minimum mass of H2SO4 required to dissolve the aluminum block is calculated by:

(15.4 g Al) / (2 mol Al/mol H2SO4) * 3 mol H2SO4/mol Al = 23.1 g H2SO4

The mass of H2 gas produced by the complete reaction of the aluminum block is calculated by:

(15.4 g Al) * (3 mol H2/mol Al) = 46.2 g H2

Therefore, the minimum mass of H2SO4 required to dissolve the aluminum block is 23.1 g and the mass of H2 gas produced by the complete reaction of the aluminum block is 46.2 g.