Molar Mass of Cl: A Brief Overview

Answer:

One of the key ideas in chemistry is the molar mass of an element or molecule. Here, we will look at the molar mass of chlorine and discuss why knowing this number is essential to comprehending how this element behaves. In addition, we will simplify the work for a lot of students and walk you through the process of doing an assignment.

A Brief Overview of Chlorine

When chlorine was initially discovered in 1774 by Swedish chemist Karl Scheele, scientists thought it was actually hydrochloric acid rather than a distinct element. Humphrey Davy separated sodium chloride, or table salt, into chlorine and sodium using electrolysis at the start of the 1800s, obtaining elemental chlorine in the process. With an atomic number of 17 and an atomic mass of 35,453, chlorine is an element of the XVII group of Mendeleev’s periodic table of chemical elements. It is common practice to designate Cl in the chemical molecule. The most prevalent halogen in the crust of the planet is chlorine, which is found mostly in two isotopes. It can only be found in compounds made up of several minerals because of its chemical activity.

Cl: What Is This Element in Chemistry?

• Chemical formula: Cl2.
• Empirical formula: Cl2.
• Diatomic chlorine (Cl2) is the molecular formula.
• Molecular weight: 18.7 cm³/mol.
• Periodic table values for molecular mass: 35,453 amu.
• The molar mass (35,453 amu) is always equal to the atomic mass.
• There is only one atom in chlorine, and that atom is called Cl.
• The melting point is -100,95 °C.
• Temperature of evaporation: -34,55 °C.

How To Determine the Chlorine Molar Mass?

There are five steps that you must take to determine the molar mass of chlorine:

1. Open the periodic table in a chemistry book or online. The characteristics of the chlorine atom, including its valence, number of bonds, and atomic mass units, are all available in this table.
2. The chemical equation is composed correctly by what you are about to do. Use the periodic table if you are unsure of the components that make up chlorine. A formula for a substance can be created with the help of chemical signs based on the valence of the constituent elements. The valence of elements, their chemical signs, how to calculate the least common multiple, and how to define elemental atom indices are all necessary for this. As a result, you need to obtain the chlorine formula, Cl2.
3. Now you are making another reference to the periodic table. Finding out what chlorine’s valence is might be beneficial. It can be III, V, or VI; we will let you know ahead of time because it all relies on the elemental makeup. If you need to complete some homework on chemistry, you can also open the valence table.
4. It is now possible to determine the amount of moles since you are aware of the element’s valence and other attributes. Identify each item’s total mass in the periodic table and note it down. For now, it’s just Cl. Make use of this formula:

M (N) = Mr (Cl) · 1 mol = 35,453 g/mol.

Since it is shown that the chlorine molecule is diatomic (Cl2), its relative atomic mass will be equal to:

Ar (Cl2) = 35,453 · 2 = 70,906 amu.

The chlorine molecule will have a relative molecular mass of 70,906 and a molar mass of:

M (N2) = Mr (Cl2) · 1 mol = 70,906 g/mol, or only 71 g/mol.

5. You must use Avogadro’s number to determine the mass of one element in order for the work to appear complete. In our case, it is simple:

Mr (Cl2) / NA = 35 / 6,02 · 1023 = 5,8 · 1023g is the value of m (Cl2).

An Example of Using Chlorine Molar Mass to Solve a Problem

Ques: A surplus of chlorine and 150 g of sodium combined to make 381 g of sodium chloride. When the molar mass of the chlorine equivalent is 35,5 g/mol, find the molar mass of the sodium equivalent, its equivalent, and the number of equivalents in the sample in mol.

Solution: It is evident from the NaCl substance’s formula that the reaction involves 381 – 150 = 231 g of chlorine. You can create a proportion because chemicals respond in proportion to their equivalents.

m (Na): m (Cl) = Meq (Na): Meq (Cl).

50: 231 = x: 35,5.

As a result, the sodium equivalent Meq (Na) molar mass is:

Meq (Na) = 150 · 35,5 / 231 = 23 g/mol is equal to x.