Given that a vector is the directed line segment from P(0,0) to Q(3,2). What is the magnitude of that vector?

Answer:- The magnitude of a vector is the length of the vector. In this case, the vector is the directed line segment from P(0,0) to Q(3,2). The components of the vector are 3 and 2. The magnitude of the vector can be found using the following formula:

Magnitude = sqrt(x^2 + y^2)

where x and y are the components of the vector. In this case, x = 3 and y = 2. Substituting these values into the formula, we get the following:

Magnitude = sqrt(3^2 + 2^2) = sqrt(13)

Therefore, the magnitude of the vector is sqrt(13).


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