How many valence electrons does each of the following atoms possess?

How many valence electrons does each of the following atoms possess?

a) cesium, Z = 55

c) krypton, Z = 36

b) boron, Z = 5

d) magnesium, Z = 12

Answer:

Here are the valence electron counts for the given atoms:

a) Cesium (Z = 55): 1 valence electron.

b) Krypton (Z = 36): Where the two atoms are involved in covalent bonding, the total number of valence electrons in the two atoms should be 8.

c) Boron (Z = 5): 3 valence electrons.

d) Magnesium (Z = 12): They therefore have two valence electrons and are technically speaking, non-metals.

These are the electrons that are in the last shell or the seventh shell depending on the period of an element. Their amount is defined with regard to the atom’s position in the mentioned table. Cesium is an alkali metal discovered to have one electron in its outermost shell. Krypton having atomic number 36 belongs to the category called noble gases and has all its external shelves packed with 8 electrons. Boron is listed in group 13 of the periodic table and has three valence electrons in its outer shell. Magnesium is an alkaline earth metal whose atomic number is 12, number of valance electrons is 2. These valence electron configurations give rationale for their chemical action/state, noble gas Cs, reactivity of krypton, electron deficiency of boron, and divalent nature of magnesium. The knowledge about valence electrons and their distribution aids in the explanation of chemical identities and bonding characteristics of elements in a compound.