How much heat is required to raise the temperature of 150g of iron 20∘C to 25∘C?

Answer:- Given: –
Mass of the iron, m = 150g = 0.15kg

Specific heat of iron, s = 480Jkg−1∘C−1

Initial temperature: Ti=20∘C

Final temperature

Tf=25∘C

Now, Change in temperature

ΔT=Tf−Ti=5∘C

The quantity of heat supplied is specified as

ΔQ=msΔT

……………………… (i)
Now, substituting the specified values in the above equation, we get

⇒ΔQ=(0.15×480×5)J

∴ΔQ=360J

Henceforth, the heat is required to raise the temperature of 150g of iron 20∘C to 25∘C is 360 J.