Molar Mass Of Benzene

Answer: Benzene is an aromatic chemical molecule with the formula C6H6. The benzene is composed of six carbon atoms, each of which is joined in a planar ring by one hydrogen atom. Additionally, benzene is regarded as a hydrocarbon because it only has hydrogen and carbon atoms in it. Benzene is a highly combustible gas that evaporates into the air extremely quickly. It has a light yellow color at room temperature.

The fact that gasoline contains benzene is widely acknowledged. It is widely utilized by several businesses throughout numerous industries. Scientists produce a variety of polymers, synthetic rubber, colors, veterinary medications, and more. This material is made from other industrial components, despite being found in crude oil.

The Physical Characteristics of Benzene

• Benzene burns with a brilliant, smoky flame and produces combustible fumes.
• It is a colorless, clear, highly mobile liquid containing aromatic chemicals.
• It becomes a crystalline mass in the cold and melts about 6 °C.
• This substance mixes well with a variety of organic solvents, including xylene gasoline, toluene, ether, chloride, cyclohexane, ethanol, methane, and octane.
• A maximum of 0.08% of benzene dissolves in water at 22 °C, making it nearly immiscible.
• Fats, resins, oils, asphalt, alkaloids, sulfur, phosphorus, iodine, and other materials are all well-suited for benzene as a solvent.

The Chemical Characteristics of Benzene

• Each of the six carbon atoms in the molecule is in a state of sp2 hybridization and is connected by three chemical structural bonds to two neighboring carbon atoms as well as a hydrogen atom.
• For every pair of π-bonds, the bond angles are 120 °. Therefore, all carbon atoms and ΰ-bonds C-C and H-H lay in the same plane, forming the regular hexagon that serves as the skeleton of ð-bonds.
• Benzene naturally undergoes substitution reactions. It interacts with olefins, halogens, nitrate acid, chloroalkanes, and sulfate acid.
• Rigid temperature and pressure conditions are used to cause the benzene ring to rupture.
• Substances analogous to benzene, specifically ethyl and isopropyl benzene, are generated when reacting with olefins.
• Phenyl chloride is produced through a reaction involving Cl2 and Br2 in the presence of a catalyst.

How Is the Molar Mass of Benzene Calculated?

Calculating the molar mass of benzene is simple. Here is how you can calculate it:

• Assemble the periodic table beforehand. The atomic mass unit and the valencies of chemical elements can be written down using this table.
• Coming up with a chemical formula is the next stage. Using the periodic table, you may create a formula if you know which elements are present in the substance. The components in this example are made into the formula C6H6.
• It is now time to begin using the periodic table in your work. Write the valence of each element (C, H) in the table. The task can be made simpler by utilizing the valence table. The periodic table will need to be used throughout the session because chemistry textbooks frequently do not include it.
• You can begin calculating when you have listed each element’s valencies. But first, note the weight of every ingredient before moving further. Periodic table weights are given. H weighs 1.00784 atomic weight, and C weighs 12.0107. Quantities that must be multiplied in addition to the mass are included in the formula. These formulas should be in your possession:

Mr (C6H6) = 6 · Ar (C) + 6 · Ar (H).

Mr (C6H6) = 6 · 12 + 6 · 1 = 72 + 6 = 78.

These calculations demonstrate that you must sum together all of the masses in order to determine the molar mass of ethanol.

• You are almost at the end of the process. Find out how much one molecule weighs. You must utilize the entire molar mass of benzene and the Avogadro number to accomplish this. Therefore, you can obtain the subsequent formula:

m (C6H6) = Mr (C6H6) / NA = 78 / 6,02 · 1023 = 12,9 · 1023g

An Example of Using Benzene’s Molar Mass to Solve Assignments 

Question: Determine the mass of benzene that is produced when 184.8 g of cyclohexane are dehydrogenated.

Solution: To begin, we must write the reaction equation, which is C6H14 = C6H6 + 4H2. We now need to determine cyclohexane’s v. The mass is divided by the molar mass, giving us 184,8 / 86 = 2,15 mol. 

Given that cyclohexane and benzene have the same ratio in the equation, benzene will likewise have v equal to 2,15 mol. Using the formula, we can then get the mass of benzene. The molar mass, 2,15 · 78 = 167,7g, must be multiplied by ν.

Benzene has a mass of 167,7 g.