with a period of 27.3 days. part a what is the angular momentum of the moon around the earth?
Answer:- The angular momentum of the moon around the earth is:
L = 2.88 × 10^34 kg⋅m^2⋅s^-1
where:
- L is the angular momentum
- m is the mass of the moon
- r is the distance between the moon and the earth
- T is the period of the moon’s orbit
To calculate the angular momentum, we can use the following equation:
L = mr^2ω
where:
- ω is the angular velocity of the moon
The angular velocity of the moon can be calculated using the following equation:
ω = 2π/T
Substituting these equations into the first equation, we get:
L = mr^2(2π/T)
Plugging in the known values, we get:
L = (7.4 × 10^22 kg)(3.8 × 10^8 m)^2(2π/27.3 days)
L = 2.88 × 10^34 kg⋅m^2⋅s^-1
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