You are given a 1.50-g mixture of sodium nitrate and sodium chloride. You dissolve this mixture into 100 mL of water and then add an excess of 0.500 M silver nitrate solution. You produce a white solid, which you then collect, dry, and measure. The white solid has a mass of 0.641 g. If you had an extremely magnified view of the solution (to the atomic-molecular level), list the species you would see (include charges, if any).

Answer:- When AgNO₃ solution is added to mixture of NaNO₃ and NaCl, it reacts with NaCl and gives precipitate of AgCl, that is white solid. The reaction takes place in 1:1 stoicheometric ratio as per the following balanced reaction:

NaCl + AgNO₃→ AgCl ↓ + NaNO₃. As per reaction 1 mole NaCl reacts with 1 mole AgNO₃ and gives  of solid precipitate of 1 mole AgCl.

0.641 g= = 4.47 X mole of solid AgCl is produced. This indicates 4.47 X mole NaCl = g of Nacl reacts to give 0.641 g of AgCl. Consequently, mass percentage of NaCl present in mixture== 17.33 %.